1992C - Gorilla and Permutation - CodeForces Solution

import math
n=int(input())
for i in range(0,n,1):
    l=list(map(int,input().split()))
    n=l[0]
    m=l[1]
    k=l[2]
    l1=[0]*n
    x=n-m
    j=1
    p=n
    for i in range(x,n):
        l1[i]=j
        j+=1
    for i in range(0,x):
        l1[i]=p
        p-=1
    for i in range(0,n):
        print(l1[i],end=" ")
    print(end="\n")